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610x-10980x^2=0
a = -10980; b = 610; c = 0;
Δ = b2-4ac
Δ = 6102-4·(-10980)·0
Δ = 372100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{372100}=610$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(610)-610}{2*-10980}=\frac{-1220}{-21960} =1/18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(610)+610}{2*-10980}=\frac{0}{-21960} =0 $
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